Differential operators in cylindrical coordinates: Difference between revisions

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Revision as of 01:07, 15 August 2014

$ \renewcommand{\vec}[1]{ {\bf #1} } \newcommand{\bnabla}{ \vec{\nabla} } \newcommand{\Rey}{Re} \def\vechat#1{ \hat{ \vec{#1} } } \def\mat#1{#1} $

grad, div, curl

$(\bnabla f)_r = \partial_{r}f,

     \quad
     (\bnabla f)_\theta = \frac1{r}\, \partial_{\theta} f,
     \quad
     (\bnabla f)_z = \partial_{z} f .$


$\bnabla \cdot \vec{A} = (\frac1{r} + \partial_{r}) A_r

     + \frac1{r}\,\partial_{\theta}A_\theta + \partial_{z} A_z .$


$(\bnabla \wedge \vec{A})_r =

     \frac1{r}\,\partial_{\theta} A_z - \partial_{z} A_\theta ,$

$(\bnabla \wedge \vec{A})_\theta =

     \partial_{z} A_r - \partial_{r} A_z ,$

$(\bnabla \wedge \vec{A})_z =

     (\frac1{r}+\partial_{r}) A_\theta - \frac1{r}\,\partial_{\theta} A_r .$

Laplacian

$\nabla^2 f = (\frac1{r}\partial_{r} + \partial_{rr} ) f

     +\frac1{r^2}\,\partial_{\theta\theta} f + \partial_{zz} f .$

$(\nabla^2 \vec{A})_r =

     \nabla^2 A_r - \frac{2}{r^2}\,\partial_{\theta}A_\theta 
     - \frac{A_r}{r^2} ,$

$(\nabla^2 \vec{A})_\theta =

     \nabla^2 A_\theta + \frac{2}{r^2}\,\partial_{\theta}A_r 
     - \frac{A_\theta}{r^2} ,$

$(\nabla^2 \vec{A})_z =

     \nabla^2 A_z .$

Advective operator

$(\vec{A}\cdot\bnabla\,\vec{B})_r =

     A_r\,\partial_{r}B_r + \frac{A_\theta}{r}\,\partial_{\theta}B_r 
     + A_z\,\partial_{z}B_r - \frac{A_\theta B_\theta}{r} ,$

$(\vec{A}\cdot\bnabla\,\vec{B})_\theta =

     A_r\,\partial_{r}B_\theta + \frac{A_\theta}{r}\,\partial_{\theta}B_\theta 
     + A_z\,\partial_{z}B_\theta + \frac{A_\theta B_r}{r} ,$

$(\vec{A}\cdot\bnabla\,\vec{B})_z =

     A_r\,\partial_{r}B_z + \frac{A_\theta}{r}\,\partial_{\theta}B_z
     + A_z\,\partial_{z}B_z .$

Toroidal-poloidal decomposition, axial

$\begin{eqnarray*}

     &
     \vec{A} = \bnabla \wedge(\vechat{z}\psi) + \bnabla \wedge\bnabla \wedge(\vechat{z}\phi) ,
     & \\ &
     \psi=\psi(r,\theta,z), \quad
     \phi=\phi(r,\theta,z).
     \nonumber &
  \end{eqnarray*}$

$\nabla^2_h f =

     (\frac1{r}\,\partial_{r}+\partial_{rr}) f + \frac1{r^2}\,\partial_{\theta\theta} f .$

$\vec{A}_r =

     \frac1{r}\,\partial_{\theta} \psi + \partial_{rz} \phi ,$

$\vec{A}_\theta =

     -\partial_{r} \psi + \frac1{r}\,\partial_{\theta z} \phi ,$

$\vec{A}_z =

     - \nabla^2_h \phi .$

Toroidal-poloidal decomposition, radial

$\begin{eqnarray*}

     &
     \vec{A} = \psi_0\,\vechat{\theta} + \phi_0\,\vechat{z}
     + \bnabla \wedge(\vec{r}\psi) + \bnabla \wedge\bnabla \wedge(\vec{r}\phi) ,
     & \\ &
     \psi_0=\psi_0(r), \quad
     \phi_0=\phi_0(r), \quad
     \psi=\psi(r,\theta,z), \quad
     \phi=\phi(r,\theta,z).
     \nonumber &
  \end{eqnarray*}$

$\nabla^2_c f = \frac1{r^2}\,\partial_{\theta\theta} f + \partial_{zz} f .$

$\vec{A}_r =

     -r \nabla^2_c \phi ,$

$\vec{A}_\theta =

     \psi_0 + r \partial_{z} \psi + \partial_{r\theta} \phi ,$

$\vec{A}_z =

     \phi_0 - \partial_{\theta} \psi + (2+r\partial_{r})\partial_{z} \phi .$